Thursday, 30 April 2015

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How To Find Left Recursion and Remove it Using C Program

Post By - Tanmay | 4/30/2015 10:13:00 am
In this tutorial you will learn to develop a program in which you'll find and remove left recursion.

What is left recursion ?

Left Recursion:

Consider,

E->E+T
E=a
T=b

In it's parse tree E will grow left indefinitely, so to remove it

E=Ea | b

we take as

E=bE'
E'= aE'|E

Program :

1:  #include<stdio.h>  
2:  #include<string.h>  
3:  #define SIZE 10  
4:  int main () {  
5:       char non_terminal;  
6:       char beta,alpha;  
7:       int num;  
8:       char production[10][SIZE];  
9:       int index=3; /* starting of the string following "->" */  
10:       printf("Enter Number of Production : ");  
11:       scanf("%d",&num);  
12:       printf("Enter the grammar as E->E-A :\n");  
13:       for(int i=0;i<num;i++){  
14:            scanf("%s",production[i]);  
15:       }  
16:       for(int i=0;i<num;i++){  
17:            printf("\nGRAMMAR : : : %s",production[i]);  
18:            non_terminal=production[i][0];  
19:            if(non_terminal==production[i][index]) {  
20:                 alpha=production[i][index+1];  
21:                 printf(" is left recursive.\n");  
22:                 while(production[i][index]!=0 && production[i][index]!='|')  
23:                      index++;  
24:                 if(production[i][index]!=0) {  
25:                      beta=production[i][index+1];  
26:                      printf("Grammar without left recursion:\n");  
27:                      printf("%c->%c%c\'",non_terminal,beta,non_terminal);  
28:                      printf("\n%c\'->%c%c\'|E\n",non_terminal,alpha,non_terminal);  
29:                 }  
30:                 else  
31:                      printf(" can't be reduced\n");  
32:            }  
33:            else  
34:                 printf(" is not left recursive.\n");  
35:            index=3;  
36:       }  
37:  }   

Output :



Next : Symbol Table Generator

7 comments:

  1. Why u have used string.h in code??

    ReplyDelete
  2. it does not give answers to more than 1 rule.

    ReplyDelete
  3. the solution is wrong
    if we take the grammar E->E+T|T it will produce wrong output because u are assigning only one character in alpha i.e. + but alpha should be remaining all character till "|" i.e. "+T" in this case.

    ReplyDelete
  4. this solution is wrong
    it is only correct for the grammar that have only on character after Non terminal in right side (E->ET)
    it will not work for others like (E->E+T|E)
    here alpha have two character (+T) but this program will assign only one character (+)

    ReplyDelete
    Replies
    1. I mean the execution is right there! :shrug:

      Delete